85. Maximal Rectangle

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Posted by bbkgl on April 28, 2020

雨打梨花深闭门

忘了青春

误了青春

套84的解法,以每一行往上作为柱状图,每列网上连续的‘1’为柱。

需要注意的是,heights的更新使用dp,不然还是超时。。。

class Solution {
private:
    vector<int> getEdge(vector<int> &heights, int step) {
        vector<int> hash(heights.size(), -1);
        stack<int> s;
        int start = step > 0 ? 0 : heights.size() - 1;
        int end = step > 0 ? heights.size() - 1 : 0;
        for (int i = start; i != end + step; i += step) {
            while (!s.empty() && heights[s.top()] >= heights[i])
                s.pop();
            if (s.empty()) hash[i] = start;
            else hash[i] = s.top() + step;
            s.push(i);
        }
        return hash;
    }

    int leetcode84(vector<int>& heights) {
        int ans = 0;
        vector<int> hash1 = getEdge(heights, 1);
        vector<int> hash2 = getEdge(heights, -1);
        for (int i = 0; i < heights.size(); i++) 
            ans = max(ans, heights[i] * (hash2[i] - hash1[i] + 1));
        return ans;
    }

public:
    int maximalRectangle(vector<vector<char>>& matrix) {
        int m = matrix.size(), n = 0, ans = 0;
        if (m) n = matrix[0].size();
        else return 0;
        vector<int> heights(n, 0);
        for (int i = 0; i < m; i++) {
            for (int j = 0; j < n; j++) {
                heights[j] = matrix[i][j] == '1' ? heights[j] + 1 : 0;
            }
            ans = max(ans, leetcode84(heights));
        }
        return ans;
    }
};